Chemistry Lab Report

Karolina Trelinska Chem 106 LB November 15th, 2012 Summary Precipitating in Central putting surface Warm-Up run 1 We have 3 equatings: cease chemical equality, complete noodle equation and net bean equation. The difference between them is that a complete noggin equation shows all the ions that atomic anatomy 18 adrift(p) around in the response admixtureture. The Net ionic equation only shows the ions that atomic spell 18 participating in the answer. The spectator ions are left out. For reaction (II) Pb (NO3)2 + 2KI -> PbI2+2KNO3 Lead nitrate is soluble, so it gets written as ions. The same goes for potassium iodide and potassium nitrate. consummate loft equation: 2 K+1 + I-1 + Pb2+ + NO32- -> PbI2 + 2K+1 + NO3-1 Net Ionic Equation: Pb+2 + 2 I-1 -> PbI2 Warm-Up make 2 In this lab you will mix 25 mL of 0.05M lead nitrate with 1.4 mL of 0.025M atomic flesh 11 carbonate. after the reaction occurs, you will filter the final result to pull away the precipitate. You will then test the be solution for unornamented lead ion and for excess carbonate ion consider that you mix the 2 volumes and then freeze frame the reaction so the it does non proceed: 1. Identify all the ionic species amaze in the solution before the reaction takes place. 2. Compute the thousand and the number of moles of each ionic species present before the reaction takes place.

After reaction goes to completion: 3. Identify all the ionic species present in solution 4. Compute the molarity and the number of moles of each ionic species present. 5. Clearly predict t he results of the experiment by determing wh! ich reactant is limiting and which is in excess. Pb(NO3)2(aq) + Na2CO3(aq) --> PbCO3(s) + 2NaNO3(aq) 1)Before Pb+2(aq) + NO3(aq)- + Na+(aq) + CO3-2(aq) 2)Before 25 ml of 0.05 mole Pb(NO3)2/1000ml = 0.00125 moles Pb(NO3)2(aq) Pb(NO3)2(aq) --> Pb+2(aq) + 2NO3-(aq) 0.00250 moles of NO3-(aq) and 0.00125 moles of Pb+2(aq) 1.4 ml * 0.025 mole Na2CO3/1000ml = 0.000035 moles Na2CO3(aq)...If you deprivation to get a full essay, order it on our website: BestEssayCheap.com

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